Rectangle and square
P = a · b, L = 2(a + b)Area90
- Perimeter39
- Diagonal14.151
- Area of a square with side a144
Areas and perimeters of shapes, volumes of solids, the Pythagorean theorem and trigonometry.
Most practical calculations — how much paint the walls need, how many liters a tank holds, whether an angle is a right angle — come down to a handful of area and volume formulas. The results come with the quantities derived from them: the diagonal, the slant height, the height and the circumradius.
P = a · b, L = 2(a + b)Heron's formulac = √(a² + b²)P = πr², L = 2πrP = (a + b) · h / 2V = a · b · cV = πr²hV = 4/3 πr³ ; V = πr²h / 3sin, cos, tan (in degrees)arcsin, arccos, arctan| Shape | Area | Perimeter |
|---|---|---|
| square | a² | 4a |
| rectangle | a · b | 2(a + b) |
| triangle | a · h / 2 | a + b + c |
| equilateral triangle | a²√3 / 4 | 3a |
| parallelogram | a · h | 2(a + b) |
| rhombus | d₁ · d₂ / 2 | 4a |
| trapezoid | (a + b) · h / 2 | a + b + c + d |
| circle | πr² | 2πr |
| circular sector | πr² · α / 360° | 2r + 2πr · α / 360° |
| Solid | Volume | Surface area |
|---|---|---|
| cube | a³ | 6a² |
| cuboid | a · b · c | 2(ab + ac + bc) |
| prism | Pp · h | 2Pp + Pb |
| cylinder | πr² · h | 2πr(r + h) |
| pyramid | Pp · h / 3 | Pp + Pb |
| cone | πr² · h / 3 | πr(r + l) |
| sphere | 4/3 · πr³ | 4πr² |
| Angle | sin | cos | tan | Radians |
|---|---|---|---|---|
| 0° | 0 | 1 | 0 | 0 |
| 30° | 1/2 = 0,5 | √3/2 ≈ 0,866 | √3/3 ≈ 0,577 | π/6 |
| 45° | √2/2 ≈ 0,707 | √2/2 ≈ 0,707 | 1 | π/4 |
| 60° | √3/2 ≈ 0,866 | 1/2 = 0,5 | √3 ≈ 1,732 | π/3 |
| 90° | 1 | 0 | does not exist | π/2 |
| 180° | 0 | −1 | 0 | π |
A room 5 × 4 m, 2.7 m high. We take off 3 m² of windows and doors. The paint covers 10 m² per liter and we apply two coats.
2 · (5 + 4) = 18 m18 · 2,7 = 48,6 m²48,6 − 3 = 45,6 m²45.6 · 2 = 91.2 m² to paint91.2 / 10 = 9.12 litersAnswer: About 9.2 liters of paint are needed, or 10 liters if you buy a little spare.
A tank has a radius of 40 cm and a height of 1.2 m. How many liters does it hold?
r = 40 cm = 0.4 m, h = 1.2 mV = πr²h = π · 0,16 · 1,2V = 0,6032 m³1 m³ = 1,000 liters → 603.2 litersAnswer: The tank holds about 603 liters.
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